How do you sketch the graph of #y=x^2+4# and describe the transformation?

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Answer 1 · 2018-06-13T14:22:48

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Please see the explanation.

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A Quadratic Equation in standard form:

#ax^2+bx+c=0, a !=0#

graph{x^2+4 [-40, 40, -20, 20]}

#color(red)(y=x^2# is the Parent Graph.

#color(blue)(y=x^2 +4# is the graph of the given function.

If the coefficient of the x-term (a) is positive, the graph of the parabola Opens Up.

If the coefficient of the x-term (a) is negative, the graph of the parabola Opens Down.

The value of #c# shifts the Vertex of the parabola Up or Down .

#c# is also the y-intercept.