How do you solve ${(1.011)}^{x} = 2$ $(1.011)^x=2$ ?

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How do you solve ${(1.011)}^{x} = 2$ $(1.011)^x=2$ ?

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Answer 1 · 2016-04-08T05:00:15

63,36, nearly.

Explanation:

$log (a^{n}) = - n log a$ $log (a^n)=- n log a$ .
Equating logarithms, x log 1,011 = log 2.
So, $x = \frac{log 2}{log 1.011}$ $x = log 2 / log 1.011$ = 63.36, nearly.

Check: ${1.011}^{63.36}$ $1.011^63.36$ = 2.000015, nearly 2.000, rounded to 4-sd..

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How do you solve ${(1.011)}^{x} = 2$ $(1.011)^x=2$ ?

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Science

Math

Humanities

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How do you solve (1.011)x=2 (1.011)^x=2 ?

1 Answer

Explanation:

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How do you solve ${(1.011)}^{x} = 2$ $(1.011)^x=2$ ?