How do you solve $1000e^(-4x)=75$ ?

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Answer 1 · 2016-12-26T12:07:34

$0.136 (3s.f.)$

$1000e^(-4x)=75$

convert into a logarithmic function:

$1000e^(-4x)=75$

$log_(1000e)(75)=4x$

solve this using a calculator:

$log_(1000e)(75) = 0.54598...$

$4x = 0.54598..$

divide by 4:

$x = (Ans)/4 = 0.136 (3s.f.)$

How do you solve 1000e^(-4x)=751000e^(-4x)=75?