How do you solve $100e^(-0.6x)=20$ ?

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Answer 1 · 2016-11-16T14:15:58

$x =-0.767$

$100e^(-0.6x)=20$

$e^(-0.6x)=20/100=0.2$

Applying natural log on both sides

$log_ee^(-0.6x)=log_e0.2$

$-0.6xlog_ee=log_e0.2$

$-0.6x=2.303xx0.2$

$x=-0.767$

How do you solve 100e^(-0.6x)=20100e^(-0.6x)=20?