How do you solve #10x^2 + 19x + 6 = 0# by factoring? Algebra Polynomials and Factoring Zero Product Principle 1 Answer Konstantinos Michailidis Oct 4, 2015 We have that #10x^2+19x+6=0=>10x^2+4x+15x+6=0=>2x(5x+2)+3(5x+2)=0=>(2x+3)*(5x+2)=0=>x=-3/2 or x=-2/5# Answer link Related questions What is the Zero Product Principle? How to use the zero product principle to find the value of x? How do you solve the polynomial #10x^3-5x^2=0#? Can you apply the zero product property in the problem #(x+6)+(3x-1)=0#? How do you solve the polynomial #24x^2-4x=0#? How do you use the zero product property to solve #(x-5)(2x+7)(3x-4)=0#? How do you factor and solve #b^2-\frac{5}{3b}=0#? Why does the zero product property work? How do you solve #(x - 12)(5x - 13) = 0#? How do you solve #(2u+7)(3u-1)=0#? See all questions in Zero Product Principle Impact of this question 10824 views around the world You can reuse this answer Creative Commons License