How do you solve #10x^2-6=-14x^2+10x+50#?

Question

1556 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-28T16:08:36

#x=7/4 , -4/3#

Move everything to the left side:

#24x^2-10x-56=0#

#x=(10+-sqrt(100-4(24)(-56)))/48#

#x=(10+-sqrt(5476))/48#

#x=(10+-74)/48#

#x=84/48 , -64/48#

#x=7/4 , -4/3#