How do you solve $10x^2-6=-14x^2+10x+50$ ?

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Answer 1 · 2017-03-28T16:08:36

$x=7/4 , -4/3$

Move everything to the left side:

$24x^2-10x-56=0$

$x=(10+-sqrt(100-4(24)(-56)))/48$

$x=(10+-sqrt(5476))/48$

$x=(10+-74)/48$

$x=84/48 , -64/48$

$x=7/4 , -4/3$

How do you solve 10x^2-6=-14x^2+10x+5010x^2-6=-14x^2+10x+50?