Question

How do you solve `11^(x^2) =25.4`?

Answer 1

`x=1.1614` or `x=-1.1614`

Explanation:

Taking log of both the sides in the equation `11^(x^2)=25.4`,

`x^2xxlog11=log25.4` or

`x^2=(log25.4)/log11=1.4048/1.0414=1.349`

Hence `x=+-1.1614` i.e. `x=1.1614` or `x=-1.1614`