Question

How do you solve `16x^2 - 9 = 0` by factoring?

Answer 1

See explanation

Explanation:

It is #16x^2-9=0=>(4x)^2-3^2=0=>(4x-3)*(4x+3)=0=> x=3/4 or x=-3/4#

Remarks

We used the identity `a^2-b^2=(a-b)*(a+b)`