How do you solve $16x^2 - 9 = 0$ by factoring?

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Answer 1 · 2015-09-28T02:10:45

See explanation

It is $16x^2-9=0=>(4x)^2-3^2=0=>(4x-3)*(4x+3)=0=> x=3/4 or x=-3/4$

Remarks

We used the identity $a^2-b^2=(a-b)*(a+b)$

How do you solve 16x^2 - 9 = 016x^2 - 9 = 0 by factoring?