How do you solve $2^(3x+19) = 16^(x+8)$ ?

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Answer 1 · 2015-07-19T13:38:29

$color(blue)(x=-13$

$2^(3x+19)=16^(x+8)$

$16= 2^4$
Rewriting the expression:

$2^(3x+19)=2^(4.(x+8)$

$2^(3x+19)=2^(4x+32)$

Now we can equate the powers:

$3x+19 = 4x+32$

$x= = 19-32$
$color(blue)(x=-13$

How do you solve 2^(3x+19) = 16^(x+8)2^(3x+19) = 16^(x+8)?