How do you solve 2( 5^ { 2x - 9} ) = 2502(52x−9)=250? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer CW Dec 2, 2016 x=6x=6 Explanation: 2(5^(2x-9))=2502(52x−9)=250 => 5^(2x-9)=125⇒52x−9=125 => 5^(2x-9)=5^3⇒52x−9=53 => 2x-9=3⇒2x−9=3 => 2x=12⇒2x=12 => x=6⇒x=6 Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9^(x-4)=819x−4=81? How do you solve logx+log(x+15)=2logx+log(x+15)=2? How do you solve the equation 2 log4(x + 7)-log4(16) = 22log4(x+7)−log4(16)=2? How do you solve 2 log x^4 = 162logx4=16? How do you solve 2+log_3(2x+5)-log_3x=42+log3(2x+5)−log3x=4? See all questions in Logarithmic Models Impact of this question 1181 views around the world You can reuse this answer Creative Commons License