How do you solve $2.5 = ln (x)$ $2.5 = ln(x)$ ?

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Answer 1 · 2015-07-29T21:01:11

$x = e^{2.5} \approx 12.1825$ $x=e^{2.5}approx 12.1825$

${log}_{b} (c) = d$ $log_{b}(c)=d$ is equivalent to $b^{d} = c$ $b^{d}=c$

Since $ln (x) = {log}_{e} (x)$ $ln(x)=log_{e}(x)$ , $ln (x) = 2.5$ $ln(x)=2.5$ is equivalent to $e^{2.5} = x$ $e^{2.5}=x$

How do you solve 2.5=ln(x)2.5 = ln(x)?