How do you solve $2 - 7 - {log}_{3} 8 x = 2$ $2- 7 - log _ 3 8x = 2$ ?

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Answer 1 · 2015-11-24T15:58:57

$x = \frac{1}{17496}$ $x=1/17496$

$2 - 7 - {log}_{3} 8 x = 2$ $2-7-log_3 8x=2$

$- 5 - {log}_{3} 8 x = 2$ $-5-log_3 8x=2$

$- {log}_{3} 8 x = 7$ $-log_3 8x=7$

${log}_{3} 8 x = - 7$ $log_3 8x=-7$

$3^{{log}_{3} 8 x} = 3^{- 7}$ $3^(log_3 8x)=3^-7$

$8 x = \frac{1}{2187}$ $8x=1/2187$

$x = \frac{1}{17496}$ $x=1/17496$

How do you solve 2−7−log38x=22- 7 - log _ 3 8x = 2?