Question

How do you solve `2 ln ( 3 - x ) - 4 = 0`?

Answer 1

`x=3-e^2=-4.389`

Explanation:

Take the `4` and `2` to the right:

`ln(3-x)=4/2=2`

Apply the definition of logarithm:

`log_ax=b ->x=a^b` here the base is the number `e`:

`3-x=e^2`

rearranging:
`x=3-e^2=-4.389`