Question

How do you solve `2 Log (x+7) = Log 9`?

Answer 1

`x=-4`

Explanation:

`2*log(x+7)=log9`
`=>1/2*2*log(x+7)=1/2*log9`
`=>log(x+7)=log(9^(1/2))` (the logarithm of a second root is the logarithm of the number divided by 2)
`=>log(x+7)=log3`
`=>x+7=10^log3`
Add -7 to both sides:
`x+7-7=3-7`
`=>x=-4`