How do you solve $2^{x} = 30$ $2^x = 30$ ?

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Answer 1 · 2016-03-02T16:37:14

$x = {log}_{2} (30) \approx 4.907$ $x = log_2(30)~~4.907$

We will use the following properties of logarithms:

With these, we have

$2^{x} = 30$ $2^x = 30$

$\Rightarrow {log}_{2} (2^{x}) = {log}_{2} (30)$ $=>log_2(2^x) = log_2(30)$

$\Rightarrow x {log}_{2} (2) = {log}_{2} (30)$ $=>xlog_2(2) = log_2(30)$

$\Rightarrow x (1) = {log}_{2} (30)$ $=>x(1)=log_2(30)$

$:.x = log_2(30)~~4.907$

How do you solve 2^x = 302x=302^x = 30?