How do you solve #2^(x+4) = 3^(x-1)#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer sankarankalyanam Jun 22, 2018 #x = 9.5414# Explanation: #2 ^(x+4) = 3 ^ (x-1)# #=>(x + 4) log 2 = (x-1) log 3# #=> (x+4) * 0.301 = (x-1) * 0.4772# #x (0.4772 - 0.301) = (4 * 0.301 + 0.4772)# #0.1762 x = 1.6812# #x = 1.6812 / 0.1762 = 9.5414# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1627 views around the world You can reuse this answer Creative Commons License