Question

How do you solve `2^x=4^(x+1)`?

Answer 1

`color(red)( x = -2`

Explanation:

`2^color(red)(x)=2^(color(red)(2.(x+1)`
Here as bases are equal we can equate the respective powers with each other:

`x = 2(x+1)`
`x = 2x +2`
`color(red)( x = -2`