How do you solve $2^x * 4^(x+5)=4^(2x-1)$ ?

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Answer 1 · 2015-09-30T17:21:59

x=12

Rewrite the equation with all the exponents with the same base, which would obviously 2.

$2^x * (2^2)^(x+5)= (2^2)^(2x-1)$

$2^x * 2^(2x+10) = 2^(4x-2)$

$2^(3x+10)=2^(4x-2)$

Since base is same on both sides, equate the exponents 3x+10=4x-2 and solve for x.

x=12

How do you solve 2^x * 4^(x+5)=4^(2x-1)2^x * 4^(x+5)=4^(2x-1)?