Question

How do you solve `2(x + 8) ^ (4/5) - 12 = 150` and find any extraneous solutions?

Answer 1

`x=235`

Explanation:

`2(x+8)^(4/5)-12=150`
or
`2(x+8)^(4/5)=150+12`
or
`2(x+8)^(4/5)=162`
or
`(x+8)^(4/5)=162/2`
or
`(x+8)^(4/5)=81`
or
`(x+8)=81^(5/4)`
or
`x+8=(root4(81))^5`
or
`x+8=(root4((3)(3)(3)(3)))^5`
or
`x+8=3^5`
or
`x+8=243`
or
`x=243-8`
or
`x=235`