How do you solve $(2 - x) log 4 = (5 - x) log 2$ $(2-x)log4=(5-x)log2$ ?

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Answer 1 · 2015-04-28T23:08:20

The answer is $x = - 1$ $x=-1$

log(4)= $log (2^{2})$ $log(2^2)$ = $2 log (2)$ $2log(2)$

So, you can simplify $log (2)$ $log(2)$
You have the linear equation $4 - 2 x = 5 - x \Rightarrow x = - 1$ $4-2x=5-x => x=-1$

How do you solve (2−x)log4=(5−x)log2(2-x)log4=(5-x)log2?