How do you solve # 27^(4x)=9^(x+1 ) #?

Question

5947 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-08-17T13:03:51

#color(blue)(x=1/5#

#27^(4x)=9^(x+1)#

We know that #27=3^3 and 9=3^2#

So our expression can be re written as

#3^(3(4x))=3^(2(x+1)#

#3^(12x)=3^(2x+2)#

As the bases are equal we can equate the exponents.

#12x=2x+2#

#12x-2x=2#

#10x=2#

#color(blue)(x=1/5#