Question

How do you solve `27^(x+2)=3`?

Answer 1

`27^(x+2)=3`

`27` can be written as `(3)^3`

the expression now becomes:
`(3)^(3.(x+2)) = (3)^1`

equating exponents:
`3.(x+2) = 1`

`3x+6 = 1`

`x= -5/3`