How do you solve $2 e^{12 x} = 18$ $2e^(12x) = 18$ ?

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Answer 1 · 2016-04-01T12:23:01

$\frac{ln 9}{12}$ $ln9/12$

$2 e^{12 x} = 18$ $2e^(12x)=18$
$e^{12 x} = 9$ $e^(12x)=9$
$ln (e^{12 x}) = ln (9)$ $ln(e^(12x))=ln(9)$
$12 x ln (e) = ln (9)$ $12xln(e)=ln(9)$

$ln (e) = 1$ $ln(e)=1$

So

$x = \frac{ln (9)}{12}$ $x=ln(9)/12$

How do you solve 2e12x=182e^(12x) = 18?