How do you solve $2e^x-5e^x-3=0$ ?

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Answer 1 · 2016-07-23T17:33:02

$2e^x -5e^x$ is $-3e^x$ , therefore your equation is equivalent to $e^x =-1$ : no solution, because $e^x>0$ for any real $x$ .

How do you solve 2e^x-5e^x-3=02e^x-5e^x-3=0?