How do you solve #-2x^2+13x=15#?

Question

3012 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-31T16:35:35

#-2x^2+13x=15#

#=>#

# x=5 or x=3/2#

Remember the standard form of a quadratic is #ax^2+bx+c#

So first we put the equation into standard form

#-2x^2+13x=15#

#<=># subtract #15# from both sides

#-2x^2+13x-15=0#

Then we can factor this equation

#(-2x+3)(x-5)=0#

Then we see that #x# could equal #5#

or

#(-2x+3)=0#

#<=>#

#-2x=-3#

#<=>#

#x=3/2#

#therefore x=5 or x=3/2#