How do you solve $2x^2+3x-17=0$ by completing the square?

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Answer 1 · 2016-06-18T15:15:21

$x=(-3+-sqrt145)/4$

step by step

$2x^2+3x-17=0$

$2x^2+3x=17$

$x^2+3/2x=17/2$

$x^2+3/2x+9/16=17/2+9/16$

$(x+3/4)^2=145/16$

$x+3/4=+-sqrt145/4$

$x=(-3+-sqrt145)/4$

How do you solve 2x^2+3x-17=02x^2+3x-17=0 by completing the square?