How do you solve 2x^2 - 6x +1 = 0 by completing the square?

1 Answer
Nallasivam V
Jan 21, 2017

x=sqrt(7/4)+3/2

x=-sqrt(7/4)+3/2

Explanation:

Given -

2x^2-6x+1=0

2x^2-6x=-1

(2x^2)/2-(6x)/2=(-1)/2

x^2-3x=(-1)/2

x^2-3x+9/4=(-1)/2+9/4

(x-3/2)^2=(-2+9)/4=7/4

(x-3/2)=+-sqrt(7/4)

x=sqrt(7/4)+3/2

x=-sqrt(7/4)+3/2

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