How do you solve 2x27x+4=0 using completing the square?

1 Answer
Jun 16, 2015

The answers are x=12 and x=4.

Explanation:

First, factor the coefficient of x2 out of the first two terms to get 2x27x+4=2(x2+72x)+4=0.

Next, take the coefficient of x inside the parentheses, 72, divide it by 2 to get 74, and then square that number to get 4916. Add this number inside the parentheses and then "balance" it by adding 24916 on the other side of the equation to get 2(x2+72x+4916)+4=24916=498.

The reason this trick is a good idea is that the expression x2+72x+4916 is a perfect square. It equals (x+74)2, so the equation becomes 2(x+74)2+4=498, which is equivalent to 2(x+74)2=818 and (x+74)2=8116.

Now take the ± square root of both sides to get x+74=±94, leading to two solutions x=9474=24=12 and x=9474=164=4.

You should check these in the original equation:

x=122(12)27(12)+4=1272+4=4+4=0

x=42(4)27(4)+4=32+28+4=0