How do you solve $2x^2 - 8x = 22$ by completing the square?

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Answer 1 · 2016-05-14T11:52:44

$x=5.87(2dp) and x= -1.87(2dp)$

$2(x^2-4x+4)=22+8 or 2(x-2)^2=30 or (x-2)^2=15or x-2 = +-sqrt15 or x=2+sqrt15=5.87(2dp) and x=2-sqrt15= -1.87(2dp)$ [Ans]

How do you solve 2x^2 - 8x = 222x^2 - 8x = 22 by completing the square?