How do you solve #2x^2+9x+9=0#?
2 Answers
May 20, 2017
Explanation:
Plug the values into the Quadratic Formula
May 20, 2017
Explanation:
#"'splitting' the middle term to give"#
#2x^2+6x+3x+9=0#
#"taking out a common factor from each 'pair'"#
#color(red)(2x)(x+3)color(red)(+3)(x+3)=0#
#"taking out the common factor " (x+3)#
#(x+3)(color(red)(2x+3))=0#
#"equate each factor to zero"#
#x+3=0tox=-3#
#2x+3=0tox=-3/2#
#color(blue)"As a check"#
#2(-3)^2+9(-3)+9=18-27+9=0rarr" True"#
#2(-3/2)^2+9(-3/2)+9=9/2-27/2+18/2=0#
#rArrx=-3" or " x=-3/2" are the solutions"#