How do you solve #2x^2-x-6=0# by factoring? Algebra Polynomials and Factoring Zero Product Principle 1 Answer Alan P. Oct 7, 2015 #x=-3/2# or #x=2# Explanation: #2x^2-x-6# #color(white)("XXX")=(2x+3)(x-2)# So #2x^2-x-6=0# #rarrcolor(white)("XXX")(2x+3)=0color(white)("XXX)#or#color(white)("XXX)(x-2)=0# #rarrcolor(white)("XXX")x=-3/2color(white)("XXXXX)#or#color(white)("XXX)x=2# Answer link Related questions What is the Zero Product Principle? How to use the zero product principle to find the value of x? How do you solve the polynomial #10x^3-5x^2=0#? Can you apply the zero product property in the problem #(x+6)+(3x-1)=0#? How do you solve the polynomial #24x^2-4x=0#? How do you use the zero product property to solve #(x-5)(2x+7)(3x-4)=0#? How do you factor and solve #b^2-\frac{5}{3b}=0#? Why does the zero product property work? How do you solve #(x - 12)(5x - 13) = 0#? How do you solve #(2u+7)(3u-1)=0#? See all questions in Zero Product Principle Impact of this question 16533 views around the world You can reuse this answer Creative Commons License