How do you solve $2 x (x - 5) = 0$ $2x(x-5)=0$ ?

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Answer 1 · 2017-06-14T02:55:58

$x = 0, 5$ $x=0,5$

There are two solutions.

$2 x (x - 5) = 0$ $2x(x-5)=0$

Divide both sides by $2$ $2$ .

$x (x - 5) = 0$ $x(x-5)=0$

Find the values for $x$ $x$ .

$x = 0$ $x=0$ and $x - 5 = 0$ $x-5=0$ .

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$x - 5 = 0$ $x-5=0$

Add $5$ $5$ to both sides.

$x = 5$ $x=5$

How do you solve 2x(x−5)=02x(x-5)=0?