How do you solve #3 = 1.001^(12x) #? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Binayaka C. Apr 2, 2018 Solution: #x ~~91.60 # Explanation: # 3= 1.001^(12x)# Taking natural log on both sids we get, #ln (3)= 12x*ln (1.001) or 12x = ln (3)/ln (1.001)# or #12x ~~1099.1615 or x ~~ 1099.1615/12~~91.60 # Solution: #x ~~91.60 # [Ans] Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1428 views around the world You can reuse this answer Creative Commons License