How do you solve $3^{1 + 2 x} = 243$ $3^(1 + 2x) = 243$ ?

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Answer 1 · 2015-08-19T06:30:08

$x = 2$ $color(blue)(x=2$

$3^{1 + 2 x} = 243$ $3^(1+2x) =243$

$243 = 3^{5}$ $243=3^5$

So,
$3^{1 + 2 x} = 3^{5}$ $3^(1+2x) =3^5$

As bases are equal we equate the powers.

$1 + 2 x = 5$ $1+2x=5$

$2 x = 5 - 1$ $2x=5-1$

$2 x = 4$ $2x=4$
$x = 2$ $color(blue)(x=2$

How do you solve 31+2x=2433^(1 + 2x) = 243?