How do you solve #3.1^ (a-3) =9.42#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer A. S. Adikesavan May 3, 2016 #a=3+log 9.42/log 3.1=4.982#, nearly. Explanation: Use #log m^n=n log m. Equating logarithms, #(a-3)log 3.1=log 9.42# Solving for a, #a=3+log 9.42/log 3.1=4.982#, nearly. Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1787 views around the world You can reuse this answer Creative Commons License