How do you solve $3^{- 2 x + 1} \cdot 3^{- 2 x - 3} = 3^{- x}$ $3^(-2x+1) * 3^(-2x-3) = 3^(-x)$ ?

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Answer 1 · 2016-03-15T16:30:57

x = $- \frac{2}{3}$ $-2/3$

Use $a^{m} a^{n} = a^{m + n}$ $a^m a^n = a^(m+n)$ .

$3^{- 2 x + 1 - 2 x - 3} = 3^{- x}$ $3^(-2x+1-2x-3) = 3^-x$

Compare exponents. $- 4 x - 2 = - x$ $-4x-2=-x$
x = $- \frac{2}{3}$ $-2/3$ .

How do you solve 3−2x+1⋅3−2x−3=3−x3^(-2x+1) * 3^(-2x-3) = 3^(-x)?