How do you solve #3^(2x+1)=5^200#?

Question

2635 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-30T15:10:02

#=>x=(200log5-log3)/(2log3)#

#3^(2x+1)=5^200#

Taking log on both sides we have

#log(3^(2x+1))=log(5^200)#

#=>(2x+1)log(3)=200log(5)#

#=>2xlog3+log3=200log5#

#=>2xlog3=200log5-log3#

#=>x=(200log5-log3)/(2log3)#