How do you solve $3^(2x+1) = 5^(x+2)$ ?

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Answer 1 · 2016-05-19T10:18:02

$x=(2 log 5 - log 3)/(2 log 3 - log 5 )=3.607$ , nearly.

Equating logarithms,

$(2x+1)log 3=(x+2)log 5$

So, $x=(2 log 5 - log 3)/(2 log 3 - log 5 )=3.607$ , nearly.

How do you solve 3^(2x+1) = 5^(x+2)3^(2x+1) = 5^(x+2)?