Question

How do you solve `3^(2x)=80`?

Answer 1

`x~~1.994" to 3 dec. places"`

Explanation:

`"note that "3^(2x)=(3^2)^x=9^x`

`rArr9^x=80`

`[logx^nhArrnlogx]`

`"take the ln (natural log) of both sides"`

`ln9^x=ln80`

`rArrxln9=ln80`

`rArrx=ln80/ln9~~1.994" to 3 dec. places"`