How do you solve $3^{4 log x} = 5$ $3^(4logx) = 5$ ?

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Answer 1 · 2016-10-29T19:31:07

$x = 10^{\frac{log 5}{log 81}}$ $x = 10^(log5/log81)$

$log (3^{4 log x}) = log 5$ $log(3^(4logx)) = log5$

$(4 log x) log 3 = log 5$ $(4logx)log3 = log5$

$4 log x = \frac{log 5}{log 3}$ $4logx = log5/log3$

$log x = \frac{\frac{log 5}{log 3}}{4}$ $logx = (log5/log3)/4$

$log x = \frac{log 5}{log 81}$ $logx = log5/log81$

$x = 10^{\frac{log 5}{log 81}}$ $x = 10^(log5/log81)$

Hopefully this helps!

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