Question

How do you solve `3 log_2 (x-1)=5 - log_2 (4)`?

Answer 1

It is `x=3`

Explanation:

It is

#3 log_2 (x-1)=5 - log_2 (4)=>log_2(x-1)^3+log_2 4=5=> log_2(4*(x-1)^3)=5=>4*(x-1)^3=2^5=>(x-1)^3=2^3=>x-1=2=>x=3 #

Of course from the definition of the logarithm is

`x-1>0=x>1`