Question

How do you solve `3=log_x125`?

Answer 1

`x=5`

Explanation:

`3=log_x125`

`3=log_x 5^3`

`3=3*log_x 5`

`3/3=log_x 5`

`log_x 5=1`

`so ; x^1=5`

`x=5`