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How do you solve $3^{x - 1} = 27$ $3^(x-1)=27$ ?

1 Answer

Dec 30, 2016

$x = 4$ $color(green)(x=4)$

Explanation:

Note that $3^{3} = 3 \times 3 \times 3 = 27$ $3^3=3xx3xx3=27$

So if $3^{x - 1} = 27$ $3^(x-1)=27$
then
$XXX x - 1 = 3$ $color(white)("XXX") x-1=3$
which implies x=4#

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