How do you solve $3^{x - 2} = 27$ $3^(x-2)=27$ ?

Question

5673 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-23T09:40:34

$3^{x - 2} = 27$ $3^(x-2)=27$

27 can be written as $3^{3}$ $3^3$

$3^{x - 2} = 3^{3}$ $3^(x-2)=3^3$
at this stage exponents can be equated

$x - 2 = 3$ $x-2 = 3$

$x = 5$ $color(blue)( x = 5$ is the solution for the expression.

How do you solve 3x−2=273^(x-2)=27?