How do you solve $3 (x - 2) ln 2 = 99$ $3(x-2)ln2=99$ ?

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How do you solve $3 (x - 2) ln 2 = 99$ $3(x-2)ln2=99$ ?

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Answer 1 · 2015-09-10T23:35:33

$x = 2 + \frac{33}{ln 2}$ $x=2+33/ln2$

Explanation:

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$3 (x - 2) \cdot ln 2 = 99 \Rightarrow (x - 2) = \frac{99}{3 ln 2} \Rightarrow x - 2 = \frac{33}{ln 2} \Rightarrow x = 2 + \frac{33}{ln 2}$ $3(x-2)*ln2=99=>(x-2)=99/(3ln2)=>x-2=33/ln2=>x=2+33/ln2$

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How do you solve $3 (x - 2) ln 2 = 99$ $3(x-2)ln2=99$ ?

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How do you solve $3 (x - 2) ln 2 = 99$ $3(x-2)ln2=99$ ?