How do you solve $3^(x-4)= 27^(x+2)$ ?

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Answer 1 · 2016-06-16T14:07:02

The answer is $x=-5$

$3^(x-4)=27^(x+2)$

First step is to write $27^(x+2)$ as the power of $3$

$3^(x-4)=3^(3(x+2))$

Now you can write this equation as the equation of exponents:

$x-4=3(x+2)$

$x-4=3x+6$

$x-3x=6+4$

$-2x=10$

$x=-5$

How do you solve 3^(x-4)= 27^(x+2)3^(x-4)= 27^(x+2)?