How do you solve #3^x = 7#?
1 Answer
Apr 3, 2016
x ≈ 1.77
Explanation:
Using the following ' rule of logs '
#• logx^n = nlogx # Take log of both sides. We can use log to any base. I'll use ln which is the
# log_e# hence
# ln3^x = ln7 # using the rule from above :
# xln3 = ln7 → x = ln7/ln3 ≈ 1.77 #
