How do you solve $30-5(4^2-8÷4-5*2)$ ?

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Answer 1 · 2016-04-28T14:39:47

$10$

According to B.E.D.M.A.S., simplify the expression within the brackets. Start by simplifying the exponents.

$30-5(color(red)(4^2)-8-:4-5*2)$

$=30-5(color(red)(16)$ $color(blue)(-8-:4)-5*2)$

Multiply/divide the numbers from left to right within the brackets.

$=30-5(16$ $color(blue)(-2)$ $color(darkorange)(-5*2))$

$=30-5(color(teal)(16-2)$ $color(darkorange)(-10))$

Subtract the numbers from left to right within the brackets.

$=30-5(color(teal)14-10)$

$=30$ $color(purple)(-5(4))$

Multiply $-5$ by $4$ .

$=30$ $color(purple)(-20)$

$=10$

How do you solve 30-5(4^2-8÷4-5*2)30-5(4^2-8÷4-5*2)?