What is $7 - 3 (- 8 - 2) + 6 \div 2$ $7-3(-8-2) + 6 -:2$ ?

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Answer 1 · 2018-03-10T00:32:49

40

We can use PEMDAS:

$P$ $color(red)(P)$ - Parentheses (also known as Brackets)
$E$ $color(blue)(E)$ - Exponents
$M$ $color(green)(M)$ - Multiplication
$D$ $color(green)(D)$ - Division (this has the same weight as M and so I gave it the same colour)
$A$ $color(brown)(A)$ - Addition
$S$ $color(brown)(S)$ - Subtraction - (again, same weight as A and so the same colour)

First we have a $P$ $color(red)(P)$ :

$7 - 3 (- 8 - 2) + 6 \div 2$ $7-3color(red)((-8-2))+6 -:2$

$7 - 3 (- 10) + 6 \div 2$ $7-3color(red)((-10))+6 -:2$

Next we have an $M$ $color(green)(M)$ and a $D$ $color(green)(D)$

$7 - 3 (- 10) + 6 \div 2$ $7color(green)(-3(-10))+color(green)(6 -:2)$

$7 + 30 + 3$ $7color(green)(+30)+color(green)(3)$

And now we have $A$ $color(brown)(A)$

$7 + 30 + 3 = 40$ $color(brown)(7+30+3)=40$

What is 7−3(−8−2)+6÷27-3(-8-2) + 6 -:2?