How do you solve $32^(1-2X) = 8^(1/3)$ ?

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Answer 1 · 2015-08-19T06:28:38

$color(blue)(X=2/5$

$32^(1-2X)=8^(1/3$

We know that $32=2^5$ and $8=2^3$

$2^(5(1-2X))=2^(3/3$

$2^(5(1-2X))=2^1$

Now as bases are equal we equate the powers

$5(1-2X) = 1$

$5-10X = 1$

$5-1 = 10X$

$4=10X$
$X=4/10$
$color(blue)(X=2/5$

How do you solve 32^(1-2X) = 8^(1/3)32^(1-2X) = 8^(1/3)?